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How to multiply complex numbers Videos

Multiplying Complex Numbers

TabletClass Math //www.tabletclass.com video explains how to multiply complex numbers.

User Comments

sdgfargerg gregearger commented on 19 Apr 2013

I don't fucking know why I pay for class. This is free and i actually understand what he is saying.

Shairyl Tablante commented on 24 Sep 2012

I am the 3,709 student who watched to learn about this confusing math problem thanks yooww ='')))

Wendy Kestler commented on 11 Dec 2014

THANK YOU! The best! You made it so simple. :)

uiop0001 commented on 23 Nov 2015

Well done, this is great. Helped so much

reign supreme commented on 18 Oct 2011

you're really good at writing on a computer

HANI Darker commented on 06 Mar 2015

أشكرك .. ساعدتني كثيرا

gonevamyth commented on 19 Jan 2012

very helpful! thanks for the vid

D0unutMan commented on 03 Jan 2012

I love u know :D no homo though

gesminess commented on 29 Sep 2011

Thank goodness for this video

1234lilspooky commented on 05 Feb 2012

Thanks man it really helped

Ted Lacey commented on 18 Jun 2015

So grateful, man!

Dalia stefano commented on 26 May 2012

Thank you very much

Gaby Gonzales commented on 21 Aug 2012

Thank you so much!

Robert Vazquez commented on 01 Mar 2011

great video

tito ism commented on 26 Nov 2012

thank man!

Complex numbers - Multiplying and Dividing

Learn how to multiply and divide complex numbers in this step by step video. To see all my videos check out my channel page //YouTube.com/MathMeeting.

User Comments

ruth matona commented on 09 Dec 2015

it was very helpful thank u eternally

Math Meeting commented on 09 Dec 2015

+ruth matona You are very welcome!

Pranuthi Karri commented on 03 Sep 2015

how to multiply (3+i)(1-i)(-1+i)

Pranuthi Karri commented on 28 Sep 2015

+FlyingJetpack1 thanks for your answer

FlyingJetpack1 commented on 23 Sep 2015

Because it's only multiplication, there is no order to the way you should do it.Just pick two complex numbers, and multiply them with one another. After you got the sulotion to that action, multiply it with the complex number you haven't used yet, for example:(1-i)(-1+i)= (-1)+i+i+i² = (-1) + i + i + (-1) = [2i - 2]Now you take this solution and multiply it by the one we didn't use:(3+i)(2i-2)= (-6) + 6i + (-2i) + 2i² = [ -8 + 4i ]

Complex Numbers: Multiplying - Ex 1

Complex Numbers: Multiplying - Ex 1. In this video, I do a couple examples of multiplying two complex numbers and simplifying!

User Comments

JaredL607 commented on 11 May 2010

@schlynn I looked through and the closest I could find to it was factoring trinomials. I didn't see anything about binomials or binomial theorem. I might have missed it, but I doubt he's made one since binomial theorem is a little higher math than what his target audience seems to be.

showABCshow commented on 11 May 2010

Do you have anything with generating functions? Those are cool :) Another question.. do you have these ready, or do randomly think "OK let's do some complex numbers and upload to YouTube"

JaredL607 commented on 11 May 2010

You should do a video explaining binomial theorem. I think it's pretty cool and I'm sure a lot of your viewers would appreciate being able to expand binomials this way. :)

prolarka commented on 17 May 2010

@JaredL607 u mean, he sud make a video about its proof? bcuz there r many explanations (how to use) on the net (even patrick has 2 vids about that)

Sean Hardman commented on 14 Mar 2012

Thats funny both had short cuts to foiling. The first one you could have used (A+B)^2=A^2+2AB+B^2. The second one was (A^2-B^2)=(A-B)(A+B)

schlynn commented on 11 May 2010

@JaredL607 I'm pretty sure that he has a video of that. Try searching on his youtube page.

Irene Garris commented on 05 Jul 2013

I appreciate that you take time out of your day to help struggling students. Thanks!

Jihurda Ivanich commented on 27 Dec 2012

it's obviously..

Algebra - Complex Numbers

Now... YAY MATH would like to introduce to you the imaginary number " i " ! Check out how we simplify expressions involving the square roots of negative ...

User Comments

April Nobles commented on 02 Dec 2015

Thank you, thank you thank you!!!!

April Nobles commented on 02 Dec 2015

+April Nobles I also 2nd the fact that your 5's look like S's

Jared Brown commented on 11 Nov 2015

Having a test in 2 days on all of this plus factoring. Wish me luck lol, if it werent for your videos I would fail easily quite honestly.

Jared Brown commented on 21 Nov 2015

+Santy MunozGot a 75% on it which I am actually pretty happy with. Just screwed up on the ones where I was solving for X

Santy Munoz commented on 21 Nov 2015

How did you do?

Danica Uzer commented on 09 Nov 2015

I have a question, I am stuck on one problem and i dont understand how to find the end result. the problem is -4i(-9-7i)^2 I worked it out two different ways, but they dont match the answer choices i have, so i feel im doing it wrong. My first way i attempted to do is this.. -4i(-9-7i)(-9-7i) ------ I distributed -4i into the first set of parentheses and then "FOIL" the solution into the second set. (36i+28i^2)(-9-7i) -324i-252i^2 -252^2 -196i^3 which then gave me this... -326i-504i^2 -196i^3 the second way i attempted was... -4i(-9-7i)^2 (36i+28i^2)^2 (36i+28i^2)(36i+28i^2) 1296i^2 -1008i^3 +1008i^3 -784 and these are my answer choice options A. 504-128i B. 504i-504i^2-196i^3 c. -128i D. -128-504i

CounterHype C commented on 30 Nov 2015

+Danica Uzer The answer is (A). 1) Foiling (-9-7i)^2 = (81 + 63i + 63i + 49i^2) [i^2 = -1 ]2) Simplified to (81 +126i -49) = (32 + 126i)3) that qauntity multiplied by -4i (32 + 126i) = 128i - 504i^2 = -128i + 504 or simply switched is 504 - 128i [i^2 = -1]

MyDeath0 commented on 19 Jul 2015

Can you guys tell me in what class you take complex numbers in the US?

Addison Wyatt commented on 01 Dec 2015

I mean as well

Addison Wyatt commented on 01 Dec 2015

+Jonathan Loynaz Im in the IB program to

dana alghamdi commented on 28 Nov 2015

+FerreneMachine me too. i have a test on this tomorrow.

Jonathan Loynaz commented on 06 Oct 2015

+MyDeath0 im in 9th grade. but im in the IB diploma programme. so we have algebra 2 freshamn year

Someone commented on 02 Sep 2015

im in 9th grade honors and i have it

Karene Valdez commented on 02 Sep 2015

I am in algebra 2, I am a sophomore

FerreneMachine commented on 24 Aug 2015

Algebra 2. I'm taking it junior year

youmils03 commented on 19 Apr 2015

Square root of 81 is also -9, so square root of -81 is also -9i.

New Brain Order commented on 22 Jul 2015

+youmils03 So √-81' + √-81' = 0 ? as you said (-9i)+(9İ) = 0 :D

Complex Numbers - Multiplying and Dividing

Complex number worksheet with detailed solutions made by me: ...

User Comments

saldunlop commented on 14 May 2015

welcome to the future of math. Great explanations and ability to reply parts over and over. Math Teachers are obsolete and should be fired. I got a B in my class PURELY by using patrick JMT videos.

Untitled Name commented on 08 Dec 2015

in class a teacher is teaching like 20 people at the same time, and you are stressed probably cause you are not in the mood to study, its early morning, stuck with 20 people, bla blabut on youtube, its just a video you can control how freely you want, you can do it whenever you like, (probably midnight before tests lol) while eating your favourite junk food

MJIndian commented on 26 Jun 2015

+saldunlop That's probably because you can pause and rewatch certain parts in videos, unlike actual math classes where the teacher may be reluctant to go back due to time constraints

MaDDTELEVISION commented on 03 Jun 2015

rekt

patrickJMT commented on 14 May 2015

I was a math teacher before I made videos. Was I obsolete back then and should I have been fired?

Michaela Stalter commented on 22 Mar 2015

What about square root of -2 over square root of 6? I'm confused on how to simplify

Matthew Stalter commented on 22 Sep 2015

Cool

starz6x9babe commented on 20 Apr 2015

Pull out square root of 2 times i on numerator over square root of 3 times square root of 2 on denomenator. Square roots of 2 cancel left with i over square root 3. Multiply by square root of 3 over square root over 3 (don't want radical in denomenator). Comes out to square root of 3 over 3 all times i.

Foulrs18 commented on 13 Feb 2015

What if the denominator was -4 - i instead? Would the conjugate be -4 + I or 4 + i? ...

Foulrs18 commented on 25 Feb 2015

thanks :

Sello Arthur commented on 17 Feb 2015

-4+i The real part(Re) doesn't change when doing the conjugate, only the imaginary (Im) does

Complex Numbers: Adding, Subtracting, Multiplying, and Dividing

How to add, subtract, multiply, and divide complex numbers.

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