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Physics - Mechanics: Work, Energy, and Power (1 of 20) Basics

Visit //ilectureonline.com for more math and science lectures! In this video I will explain the basic concept of work, energy, and power.

User Comments

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Quynh Tran commented on 07 Dec 2015
Can I ask if 4510J is delta K (Kf - Ki) or it's just simply Kf?
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Michel van Biezen commented on 07 Dec 2015
+Quynh Tran Assuming the block started from rest, that would be the final KE = total KE
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Sarah Groleau commented on 08 Nov 2015
Thank you for your videos, can you explain again why the force of friction is positive when you are calculating work? I thought the force of friction was negative because the direction of motion dictates a positive sign? Could you clarify please?
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Sarah Groleau commented on 09 Nov 2015
I understand now, the F required to overcome the friction is positive since it is going in the positive x direction, and because of the motion. If it were the reverse, would that mean the F required to overcome the friction would still be positive? because the direction of motion is positive?
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Michel van Biezen commented on 08 Nov 2015
+Sarah Groleau The friction force is a vector quantity. As such the magnitude of a vector cannot be negative.According to the way the problem is set up, the friction force is directed to the left, which by definition is a negative direction. The force required to overcome the friction is directed to the right. The work done to overcome friction is a positive quantity. What would it be if the problem was drawn in the opposite direction?
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Michael Sobalvarro commented on 04 Nov 2015
The friction in this problem was kinetic friction, not static friction, correct?
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Michel van Biezen commented on 04 Nov 2015
+Michael Sobalvarro That is correct
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Magnus Robinson commented on 15 Oct 2015
Best Physics channel: Michel van Biezen. Best math channel: PatrickJMT. Thank you guys!!!
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Newbport commented on 27 Oct 2015
+Magnus Robinson The big homie patrick.
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chuck jones commented on 29 Sep 2015
where'd he get µ of 0.2? isn't it 100÷5kg(9.8)=100/49=2.04?
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chuck jones commented on 30 Sep 2015
d'oh...now i see it
https://lh5.googleusercontent.com/-iP_PNTIR0b4/AAAAAAAAAAI/AAAAAAAAACw/sGq4iLw1m8k/photo.jpg?sz=64
Michel van Biezen commented on 29 Sep 2015
+chuck jones the coefficient of friction was given in the problem to be 0.2

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