+blackfoxmp5 actually I see where cos x comes from, but now I'm baffled regarding why the sin term was squared and was not distributed like the original problem.
+Michel van Biezen at first you stopped at ( 1+2 sin x + sin^2 x ) / cos^2 x and then realized that there was a problem. You did squared the 1-sin x term over cos x after pointing back to the beginning of the problem. I'm confused about how you got cos x in the denominator after redoing the problem. Thanks!
Not sure which cos x you are referring to.Are you asking about (sin x)*2 + (cos x)^2 = 1?If yes, that is a basis identity in trigonometry. Look at the videos that explain those.
Verify Identities that require use of double angle identities
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//www.freemathvideos.com In this video tutorial I show you how to verify trigonometric identities. We verify trigonometric identities by following a couple of ...
sweet! you deserve the credit, great job staying with it
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//www.freemathvideos.com In this video tutorial I show you how to verify trigonometric identities. We verify trigonometric identities by following a couple of ...
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