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University of washington tacoma msl Videos

MSL Summer Session 2009

MSL Summer 2010 Slideshow

MSL Curiosity Entry, Descent & Landing Trajectory

This video shows the EDL trajectory of the MSL Curiosity rover starting from just after the entry interface up until touchdown. The trajectory data is interpolated ...

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https://gp3.googleusercontent.com/-373iKKYQriM/AAAAAAAAAAI/AAAAAAAAAAA/WKDPaELH7sI/s48-c-k-no/photo.jpg?sz=64
Note that the original data is referenced to inertial space with respect to Mars. Longitude, latitude, and altitude are determined after moving into a rotating system to compensate for the planet's spin. Altitude is simply the radial distance from Mars' center to the spacecraft minus the mean radius of Mars. If you computed the laser's path in inertial space and performed the same transformation then it would appear as a curved line with altitude increasing as the beam travels into the distance.
https://gp3.googleusercontent.com/-373iKKYQriM/AAAAAAAAAAI/AAAAAAAAAAA/WKDPaELH7sI/s48-c-k-no/photo.jpg?sz=64
Calculating the trajectory is indeed quite difficult, but simply amounts to a whole lot of math in the end. Accounting for the gravity of Earth, Mars, and the Sun (as well as the moon and Jupiter for detailed analyses) and the effects of the spin of the Earth and Mars are all necessary for computing the desired spacecraft trajectory. Timing is critical of course, much like throwing a football to a receiver that is following a pattern, but with solid engineering the vehicle will arrive on target!
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Thanks for the fast answer! So if you had used a curved Mars for this then would the first 30s of trajectory look identical, more curved or less curved? If I imagine the leading edge of the flat terrain curved down 10 degrees then do I have to "bend" the trajectory down 10 degrees also? I'm just wondering what the true trajectory would have looked like to an observer. Thanks for doing this, it's awesome. I think the guided entry is the unsung hero of this mission - it put us next to the mtn!
https://gp3.googleusercontent.com/-373iKKYQriM/AAAAAAAAAAI/AAAAAAAAAAA/WKDPaELH7sI/s48-c-k-no/photo.jpg?sz=64
The plot is orthotropic (ie. Mars does appear to be flat), but the x-, y- and z- axes are the true longitude, latitude, and altitude components of position (longitude and latitude are multiplied by mean Mars radius to have units of km). The position is derived from the trajectory which does include the curvature of the planet. The steep curve at the beginning is the atmospheric entry phase, after which the spacecraft begins a horizontal guided phase to align and reach the landing site.
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This video starts 594km downrange and 191km altitude. Is there an adjustment for curvature of Mars or have you assumed a 'flat mars'? If I fired a laser horizontally from the curiosity landing site uprange, at 600km, or 10 degrees of a martian great circle, the laser would be at an altitude of 1.5% mars radius above the surface or 53km altitude. I am wondering if the steep curve in trajectory in the first 30 seconds is guided entry or just 'mars not being flat'
https://gp3.googleusercontent.com/-373iKKYQriM/AAAAAAAAAAI/AAAAAAAAAAA/WKDPaELH7sI/s48-c-k-no/photo.jpg?sz=64
The yellow path is the ground track, or rather the position of the spacecraft over the ground (like a shadow), so if you bend it then you also need to bend the surface on which it is plotted (ie. adding the planet's curvature). While I could have plotted the data in a real inertial reference coordinate system, which includes the curvature, it would not look very different since the overall EDL trajectory is relatively small compared to the planet.
https://gp5.googleusercontent.com/-ujtCGBuJKoI/AAAAAAAAAAI/AAAAAAAAAAA/2vVNPq-PzI4/s48-c-k-no/photo.jpg?sz=64
I think this answers my question! So I would need to "bend" the yellow path down by 10 degrees at the start point and bend the green path down by some amount also. How on *Mars* do they manage to calculate these paths what with planets orbiting and spinning and gravity and such. Wow!
https://gp3.googleusercontent.com/-373iKKYQriM/AAAAAAAAAAI/AAAAAAAAAAA/WKDPaELH7sI/s48-c-k-no/photo.jpg?sz=64
Never! The ISS orbits the Earth at an altitude of about 400 km, while Mars is about 60,000,000 km away when it is closest to the Earth. With ISS having a mass of 450 tons, you'd need about 2,300 tons of rocket fuel just to reach escape velocity
https://gp3.googleusercontent.com/-h8NQfED43G0/AAAAAAAAAAI/AAAAAAAAAAA/UGqXrMYqpqA/s48-c-k-no/photo.jpg?sz=64
how long till international space station reaches mars from greencatfish52...
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Stunning! Absolutely professional work. Well done, and thanks!
https://i1.ytimg.com/i/xclRt3nUicWA57_wdzFDlA/1.jpg?sz=64
so was there any life on Mars?
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Outstanding work !!! Bravo !
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so sweet thanks!
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excellent work!
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Beautiful!

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User Comments

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Thank you, ZZZCURTIS for this awesome video!

Mars Geology: Terrain Near the Mars Science Laboratory (MSL) Landing Site

This image is of a region slightly to the southwest of where the MSL rover, called Curiosity, will land in August 2012. It shows three distinct terrains: (a) older ...

Mars Geology: A Unique View of Curiosity Rover in Yellowknife Bay July 24, 2013

This image was acquired with a large spacecraft roll to the east when the subsolar latitude was -7.26 degrees, close to the latitude of MSL (-4.6 degrees), ...

Mars Gale Crater

Mars Geology: Gale Crater animation using HiRISE DTM. This animation shows the edge of the Gale crater interior mound. It was created from NASA's HiRISE ...

This animation shows the lower reaches of Mount Sharp in Gale crater which is the destination of the MSL. It was created from NASA's HiRISE DTM and image ...

2016 IEEE Aerospace Conference and Expo - Del Mar Photonics [email protected]

2016 IEEE Aerospace Conference and Expo - please email [email protected] to arrange a meeting during the conference. Featured track and sessions ...
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